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how build (N-terminal 17 residues) structre /fragment file generation

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how build (N-terminal 17 residues) structre /fragment file generation
#1

Greetings, 

1) How to generate the n-terminal region say 17 residues (loop only, no homologs structure available in pblast )

2) Entire protein sequence structure got Robetta n-Terminal is only loop in MD run it’s not converging. 

Accordingly plan to do loop model is that way good way? or any other Rosetta application will help in is this situations

Kindly let me know  

Awaiting your replay

Post Situation: 
Wed, 2016-07-27 23:56
venkatazb

"2) Entire protein sequence structure got Robetta n-Terminal is only loop in MD run it’s not converging. "

Do you have any reason to beleive this region IS firmly structured?  If it's just a flexible tail, then MD won't converge and Rosetta won't either; it's not converged in real physics.

If you expect it to be tightly structured, continue with homology modeling or hybridize via Robetta as normal.

If you don't expect regular structure, and are just interested in a population of possible structures / determining the envelope of space the tail could occupy, try FloppyTail.  Note the C_root option if you have an N-terminal tail.  https://www.rosettacommons.org/docs/latest/application_documentation/structure_prediction/floppy-tail

Thu, 2016-07-28 07:21
smlewis

Thank you for reply,

Yes, am expecting structure  in experimental reported (“not structural studies”) N-terminal (“17 residues”) and C-terminal (with help of Abinitio relax got structure “75 residues”) are interacting with some protein (in crucial way).

May correct or not, don’t know am believe in loop structure may not get proper interactions ? 

Thank you

Fri, 2016-07-29 01:14
venkatazb

You can try loop modeling, certainly.  I think the CCD modes will let you model termini (I'm not sure).  I'm pretty sure the KIC modes won't let you model termini.  If the termini are well-structured, then homology modeling or loop modeling have a good chance of finding the correct structure.  If the terminus isn't actually well structured in solution, then Rosetta isn't going to be able to find the "one structure" as it doesn't exist anyway.

Fri, 2016-07-29 07:43
smlewis